SQL get last Monday and last Sundays date based on todays date

Published on Author Code Father

this is much cleaner solution:

SELECT
    -- 17530101 or 1753-01-01 is the minimum date in SQL Server
    DATEADD(dd, ((DATEDIFF(dd, '17530101', GETDATE()) / 7) * 7) - 7, '17530101') AS [LowerLimit], -- Last Week's Monday
    DATEADD(dd, ((DATEDIFF(dd, '17530101', GETDATE()) / 7) * 7) - 1, '17530101') AS [UpperLimit] -- Last Week's Sunday.

Which can be used like this in a real world query:

SELECT
    *
FROM
    SomeTable
WHERE
    SomeTable.[Date] >= DATEADD(dd, ((DATEDIFF(dd, '17530101', GETDATE()) / 7) * 7) - 7, '17530101') AND
    SomeTable.[Date] <= DATEADD(dd, ((DATEDIFF(dd, '17530101', GETDATE()) / 7) * 7) - 1, '17530101')

Here are some tests:

1. Leap Year

Current Date: 2016-02-29 00:00:00.000

Results:

LowerLimit                 UpperLimit
2016-02-22 00:00:00.000    2016-02-28 00:00:00.000

2. Last Week was in different year

Current Date: 2016-01-06 00:00:00.000

LowerLimit                 UpperLimit
2015-12-28 00:00:00.000    2016-01-03 00:00:00.000

3. Lower limit in previous month and upper limit in current month

Current Date: 2016-05-04 00:00:00.000

LowerLimit                 UpperLimit
2016-04-25 00:00:00.000    2016-05-01 00:00:00.000

4. Current Date is Sunday

Current Date: 2016-05-08 00:00:00.000

LowerLimit                 UpperLimit
2016-04-25 00:00:00.000    2016-05-01 00:00:00.000

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